Question

What is the value of delta G at 292 for a reaction in which deltaH = 92 kj/mol and delta S= 2.38 kj/mol K

Answer 1

Answer: The value of
`\Delta G` is -602.96 kJ/mol at 292 k for a reaction in which
`\Delta H` = 92 kj/mol and
`\Delta S` = 2.38 kj/mol K.

Step-by-step explanation:

Given: Temperature = 292 K

`\Delta H` = 92 kJ/mol

`\Delta S` = 2.38 kJ/mol

Formula used to calculate the value of
`\Delta G` is as follows.

`\Delta G = \Delta H - T\Delta S`

Substitute the values into above formula as follows.

`\Delta G = \Delta H - T\Delta S\\= 92 kJ/mol - (292 K * 2.38 kJ/mol K)\\= 92 kJ/mol - 694.96 kJ/mol\\= - 602.96 kJ/mol`

Thus, we can conclude that the value of
`\Delta G` is -602.96 kJ/mol at 292 k for a reaction in which
`\Delta H` = 92 kj/mol and
`\Delta S` = 2.38 kj/mol K.