What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough water to make a 450.0 mL solution? (Hint: must convert grams to moles first)

Question

asked Mar 11, 2023 88.4k views

1 Answer

SandOfTime · Answer 1 · 2023-03-15T02:55:41+0000

Answer:

Step-by-step explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M