Question

Can someone help me with this?

Answer 1

x^2=19^2+7^2=361+49=410
Therefore x=20.25

Answer 2

Solution given:

<J=90°[tangent to the circle is perpendicular to radius]

In right angled triangle ∆KJL

base[b]=7

hypotenuse [h]=x

perpendicular [p]=19

by using Pythagoras law

p²+b²=h²

19²+7²=x²

x=√410

x=20.248