A certain television is advertised as a 83-inch TV (the diagonal length). If the height of the TV is 45 inches, how wide is the TV? Round to the nearest tenth of an inch.

Question

asked Jul 25, 2022 100k views

2 Answers

Renato Dinhani · Answer 1 · 2022-08-01T11:01:14+0000

Answer: 69.7 inch

Explanation:

Given

A television is advertised as 83 inch TV(diagonal length)

The height of the TV is 45 inches

Suppose, width is x

Using Pythagoras theorem, we can write

$\Rightarrow 83^2=45^2+x^2\\\Rightarrow x^2=83^2-45^2\\\Rightarrow x^2=6889-2025\\\Rightarrow x=69.7\ \text{inch}$