Question

Someone help me with this please

Answer 1

Explanation:

`c=((co \ efficient \ of \ x)/(2))^(2)`

`1) c =( (8)/(2))^(2)=4^(2) =16\\\\\\2) c= ((5)/(2))^(2)=(25)/(4)\\\\\\3)c= (0.1)^(2)=0.01\\\\4)c=(b^(2))/(4)`