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Tanθ= a. 1 - cot^2 θ b. 1/cot θ c. 1 + sec^2 θ

Tanθ= a. 1 - cot^2 θ b. 1/cot θ c. 1 + sec^2 θ
asked 14.7k views
3 votes
Tanθ=

a. 1 - cot^2 θ
b. 1/cot θ
c. 1 + sec^2 θ

asked
User Shraddha Patel
by
8.2k points

1 Answer

3 votes

Answer:


tanθ = (sinθ)/(cosθ) \\ = (1)/( (cosθ)/(sinθ) ) \\ = (1)/(cotθ)

answered
User Iman
by
7.6k points
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