Question

Find the Area of the figure below, composed of an isosceles trapezoid and one

semicircle. Rounded to the nearest tenths place
10

Answer 1

Area of given figure = 48.28 unit² (Approx.)

Explanation:

Given:

Length of parallel lines are 10 , 4 respectively

Diameter of semi-circle = 4

Height of parallelogram = 6

Find:

Area of given figure

Computation:

Radius of semi-circle = Diameter of semi-circle / 2

Radius of semi-circle = 4 / 2

Radius of semi-circle = 2

Area of given figure = [1/2][Sum of parallel line][Height] + [πr² / 2]

Area of given figure = [1/2][10 + 4][6] + [(3.14)(2)² / 2]

Area of given figure = [1/2][14][6] + [(3.14)(4)/ 2]

Area of given figure = 42 + 6.28

Area of given figure = 48.28 unit² (Approx.)