Question

For what values of a and m does f(x) have a horizontal asymptote at y = 2 and a vertical asymptote at x = 1? f(x)=2x^m/x+a {a = –1, m = 1}

Answer 1

See below

Explanation:

`f(x)=(2x^(m) )/(x+a)`

`f(x)=(2x^(1) )/(x-1)`

If x=1, then 1-1=0, which implies a vertical asymptote at x=1 since dividing by 0 is undefined.