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Find the equation of the parabola with focus (5,0) and directrix x =5

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User Puk
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1 Answer

3 votes

Answer:

y²=20x

Explanation:

Note: I'm assuming you mean x=-5 for the directrix because what you're asking isn't possible

Since we are given a horizontal directrix, the parabola must also be horizontal.

Horizontal Parabola:

(y-k)² = 4p(x-h)

Vertex: (h, k)

Focus: (h+p, k)

Directrix: x = h - p

Since the focus of the parabola is (5,0), then k=0 and h+p=5. We also know that since the directrix is x=-5, then -5=h-p. If we set these equations equal to each other, we can solve for h and p:

h+p=5

h-p=-5

2p=10

p=5

Since p=5, then h=0. Therefore, we have for our equation of the parabola:

(y-k)² = 4p(x-0)

(y-0)² = 4(5)(x-0)

y²=20x

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User Ali Seymen
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