X \: varies \: as \: product \: u \: v \: and \: inversely \\ as \: their \: sum \: if \: x - 3 \: when \: u = 3 \: \\ and \: v = 1 \: what \: is \: the \: value \: of \: x \: i…

Question

`x \: varies \: as \: product \: u \: v \: and \: inversely \\ as \: their \: sum \: if \: x - 3 \: when \: u = 3 \: \\ and \: v = 1 \: what \: is \: the \: value \: of \: x \: if \\ u = 3 \: and \: v = 3`

Pls help me with this​

Answer 1

[Note that you don't have to evaluate k to solve the problem]

`x = (kuv)/((u+v))`

That means that

`x ((u+v))/((uv)) = k, a \: constant`

So, you want
`x`such that

`x ((3+3))/((3 * 3)) = 3 ((3+1))/((3 * 1))`

`x=6`