Question

An 18.0 g sample of unidentified metal was heated from 21.5°C to 89.0°C.

292 J of heat energy was absorbed by the metal in the heating process.
Calculate the specific heat of the metal to determine its identity.(need work show, or how you got the answer)

A.calcium
B.iron
C.copper
D.silver

Answer 1

Answer: (d)-Silver

Step-by-step explanation:

Given

The mass of sample is
`m=18\ gm`

It is heated from
`21.5^(\circ)C` to
`89^(\circ)C`

heat energy absorbed is
`292\ J`

Heat absorbed is given by
`Q=mc\Delta T`

Insert the values

`\Rightarrow 292=18* c* [89-21.5]\\\Rightarrow 292=18* c* 67.5\\\\\Rightarrow c=(292)/(1215)\\\\\Rightarrow c=0.24\ J/g^(\circ)C`

As per the table, it is Silver