Question

Consider an ideal gas contained in a cylinder with the volume 34.4L, temperature 667K and pressure 2atm.What will be pressure of the gas if it is heated at 1000k and the volume becomes 50L.

Answer 1

Given :

An ideal gas contained in a cylinder with the volume 34.4L, temperature 667K and pressure 2 atm.

To Find :

What will be pressure of the gas if it is heated at 1000k and the volume becomes 50L.

Solution :

We know, by ideal gas equation :

`Pv = nRT`

Now, in the given question only their are two state and also their is no leakage so amount of gas is also constant.

So,

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)\\\\(2* 34.4)/(667) = (P_2 * 50)/(1000)\\\\P_2 = (2* 34.4 * 1000)/(667 * 50)\ atm\\\\P_2 = 2.06 \ atm`

Therefore, the pressure of gas is 2.06 atm.