Question

Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC.
Prove △GEC ≅ △HFA.

Answer 1

`\\ \rm\hookrightarrow AE\cong FC`

So parallelogram BGAE and HDFC are equal.

• GE=FC

And

• BG=HD

As BG=HD

• GC=AH

Hence

`\\ \rm\hookrightarrow \triangle GEC\cong \triangle HFA(SSA)`