Question

6. A particle is moving on a straight line such that a(t) = cost, s(0) = 0, v(0) = 5.

Find the position s(t) of the particle.

Answer 1

Explanation:

St3-623t+4

St3-623t+4V=

St3-623t+4V=ds

St3-623t+4V=dsdt

St3-623t+4V=dsdtSo 3t²12 + 3 = v

St3-623t+4V=dsdtSo 3t²12 + 3 = vagain differentiate,a =

St3-623t+4V=dsdtSo 3t²12 + 3 = vagain differentiate,a =6t - 12 = 0

St3-623t+4V=dsdtSo 3t²12 + 3 = vagain differentiate,a =6t - 12 = 0t=2s

St3-623t+4V=dsdtSo 3t²12 + 3 = vagain differentiate,a =6t - 12 = 0t=2sv=3(2)² - 12 x 2+3=-9ms-1