asked 55.8k views
1 vote
Suppose you drop a ball from 120 feet. The ball will bounce to 25 of its previous height. What is the total distance the ball travels from when you let it go to the max height it reaches after the 5th bounce? Round to the nearest tenth.

A) 268.7
B)273.9
C)277.1
D)279.3

asked
User Gerdtf
by
7.8k points

1 Answer

7 votes

Answer:

277.1 feets

Explanation:

Drop height = 120 feets

Ball bounces 2/5 of previous height

Height after 1st bounce :

120 * 2/5 = 48 feets

Return distance = 48 feets

Height after second bounce :

48 * (2/5) = 19.2 feets

Return distance = 19.2 feets

Height after 3rd bounce :

19.2 * (2/5) = 7.68 feets

Return distance = 7.68 feets

Height after 4th bounce :

7.68 * (2/5) = 3.072 feets

Return distance = 3.072 feets

Height after 5th bounce :

3.072 * (2/5) = 1.2288 feets

(120 + (2*48) + (2*19.2) + (2*7.68) + (2*3.072) + 1.2288) = 277.1328

= 277.1 feets

answered
User Razvan Caliman
by
8.0k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.