Question

No bots!!!!!! When 20.4 g of sodium metal are mixed with chlorine gas, how many g of NaCl are produced?

Answer 1

51.8 g NaCl

Step-by-step explanation:

2Na(s) + Cl2(g) ---> 2NaCl(s)

20.4 g Na × (1 mol Na/22.9898 g Na) = 0.887 mol Na

0.887 mol Na × (2 mol NaCl/2 mol Na) = 0.887 mol NaCl

0.887 mol NaCl × (58.44 g NaCl/1 mol NaCl) = 51.8 g NaCl