Question

Find the surface area of a right square pyramid with base edge length

2 feet and height 5 feet.

Answer 1

24.4 sq. ft.

Explanation:

Area of a right square pyramid is:

A = a^2 + 2(a)*square root of ((a^2/4) + b^2)

A = 4 + 4 (square root of ((4/4) + 25) = 4 + 4* square root of 26

A = 4 + 4*5.099

A = 4 + 20.396

A = 24.396 sq ft.