Question

7. In A.ABC. JB and KA are medians, JK = 10x - 12, AB = 9x + 18, JM = 21, KM = 23. AJ = 60. and

BK - 52

a. Find JK and AB. Round decimal answers to the nearest tenth.
b. Find the perimeter of AABC.
c. Find the perimeter of AABM.

Answer 1

A) JK and AB =

`[tex] \boxed{( \theta) = \f{12}{( \theta)} }` So, =》
`(10)/(5) = (1)/( \( \theta) )` =》
`\( \theta) = (5)/(2)`[/tex]

B) AABC

`[tex] \boxed{( \theta) = {1}{( \theta)} }` So,
`23}{-18=\\Ans } \boxed`

C) AABM:

`[tex] e \fbox{: }` The value of k for which
`\sin(jm) = \cos(x)` is
`(\p)/(2)` ans[/tex]

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