Question

A circle has diameter of 9cm

A square has side of 5cm

Use Pythagoras Theorem to show that the square can fit into the circle without touching the edge of the circle.

Answer 1

Explanation:

diameter of the circle = 9 cm

side of square = 5 cm

As we know that the diagonal is maximum dimension in case of square, so if the length of diagonal is less than the diameter of the circle, then the square can fit into the circle else not.

First we need to find the length of the diagonal.

Let the length of diagonal is D.

By use of Pythagoras theorem

D = 7.07 cm

As the length of the diagonal is less than the diameter of the circle, so the square can fit into the circle.