Question

Find the equation of the line that is perpendicular to line

6x-5y-6= 0 and passes through the point A(6,10).

Answer 1

5x +6y -90 = 0

Explanation:

The perpendicular line will have the x- and y-coefficients swapped, and one of them negated. The constant will be chosen so the equation is satisfied at the given point.

5x +6y = 5(6) +6(10) = 90

The equation of the perpendicular line in general form is ...

5x +6y -90 = 0