Question

The first term of a linear sequence is 3 and the 8th term is 31. find the common difference​

Answer 1

The common difference is 4.

Explanation:

`a_n=a_1+(n-1)d` You get to term number n by starting with term number 1 and adding the common difference d n-1 times.

`a_1=3\text{, and }a_8=31`

`a_8=a_1+(8-1)d\\\\31=3+7d\\\\28=7d\\\\d=4`