Question

Exercise 1(a)
Write the first
six term of a A.P which
a=5, d=4​

Answer 1

5, 9, 13, 17, 21, 25

Explanation:

Given a₁ = 5 and d = 4

Add d = 4 to the previous term, that is

a₁ = 5

a₂ = a₁ + 4 = 5 + 4 = 9

a₃ = a₂ + 4 = 9 + 4 = 13

a₄ = a₃ + 4 = 13 + 4 = 17

a₅ = a₄ + 4 = 17 + 4 = 21

a₆ = a₅ + 4 = 21 + 4 = 25