Question

Find the value of x in the isosceles triangle shown below​

Answer 1

A

Explanation:

The segment from the vertex to the base , bisects the base at right angles

Then there are 2 right triangles with legs x and 4 and hypotenuse
`√(52)`

Using Pythagoras' identity in either of the 2 right angles

x² + 4² = (
`√(52)` )²

x² + 16= 52 ( subtract 16 from both sides )

x² = 36 ( take the square root of both sides )

x =
`√(36)` = 6 → A