Question

Convert 4.97 x 10' grams of ammonia (NH3) to moles of ammonia.

Answer 1

Answer: There are
`0.292 * 10^(-4) mol` are present in
`4.97 * 10^(-4) g` of ammonia.

Step-by-step explanation:

Given: Mass of ammonia =
`4.97 * 10^(-4) g`

As number of moles is the mass of substance divided by its molar mass.

Hence, moles of ammonia (molar mass = 17 g/mol) are calculated as follows.

`No. of moles = (mass)/(molar mass)\\= (4.97 * 10^(-4) g)/(17 g/mol)\\= 0.292 * 10^(-4) mol`

Thus, we can conclude that there are
`0.292 * 10^(-4) mol` are present in
`4.97 * 10^(-4) g` of ammonia.