Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today

Question

asked Jun 8, 2022 180k views

1 Answer

AKT · Answer 1 · 2022-06-13T23:41:42+0000

Answer:

$m = 10\sqrt 3$

n = 10

Explanation:

Required

Find m and n

Considering the given angle, we have:

$\sin(60) = (Opposite)/(Hypotenuse)$

This gives:

$\sin(60) = (m)/(20)$

Make m ths subject

$m = 20 * \sin(60)$

$\sin(60) =(\sqrt 3)/(2)$

So, we have:

$m = 20 *(\sqrt 3)/(2)$

$m = 10\sqrt 3$

Considering the given angle again, we have:

$\cos(60) = (Adjacent)/(Hypotenuse)$

This gives:

$\cos(60) = (n)/(20)$

Make n the subject

$n = 20 * \cos(60)$

$\sin(60) =(1)/(2)$

So, we have:

n = 20 *(1)/(2)

n = 10