Question

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A student dissolves 0.250 mol NaC1 in 2.05 kg H20. What is the molality of the resulting solution? Show your work.

Answer 1

the person below me is wrong

Step-by-step explanation:

Answer 2

`\boxed{\sf Molality=(Moles\:of\:solute)/(Mass\:of\: solvent\:in\;kg)}`

• Moles=0.25
• Mass=2.5kg

`\\ \rm\Rrightarrow Molality=(0.25)/(2.5)=0.1m`