Question

1) A negative charge of 6C exerts an attractive force of 65N on a second

charge that is 0.005 m away. What is the strength of the second charge?

Answer 1

Answer:
`30.09* 10^(-15)\ C`

Step-by-step explanation:

Given

The first charge is
`q_1=-6\ C`

Attraction force
`F=65\ N`

the second charge is at
`0.005\ m` away

Suppose the second charge is
`q_2`

The electrostatic force is given by

`F=(kq_1q_2)/(r^2)`

Insert the values

`65=(9* 10^9* 6* q_2)/([5* 10^(-3)]^2)\\\\\Rightarrow q_2=(65* 25* 10^(-6))/(54* 10^9)\\\\\Rightarrow q_2=(1625* 10^(-6-9))/(54)\\\\\Rightarrow q_2=30.09* 10^(-15)\ C`