Question

What is one value of x that makes the equation-16x^2+121=0 true

Answer 1

x = ±11/4

Explanation:

Rewrite -16x^2+121=0 as 16x^2 - 121=0 and then as 16x^2 = 121.

Take the square root of both sides. This returns 4x = ±11, and so:

x = ±11/4