Register

What is the initial value of h(t)= -9.8t2+48t+50?

What is the initial value of h(t)= -9.8t2+48t+50?
asked 80.1k views
3 votes
What is the initial value of h(t)= -9.8t2+48t+50?

What is the initial value of h(t)= -9.8t2+48t+50?-example-1
asked
User Kmikael
by
8.7k points

2 Answers

4 votes
48 is the correct answer
answered
User Timofey
by
7.7k points
4 votes

Answer:


h(t) = 9.8 {t}^(2) + 48t + 50 \\ initially : \: t = 0 \\ h(0) = 50

answered
User Xavier Delaruelle
by
7.9k points
← Prev Question Next Question →

Related questions

User Vasiliy Kulakov
asked Feb 20, 2022 9.7k views
What is the initial value of h(t)= -9.8t2+48t+50?
Vasiliy Kulakov asked Feb 20, 2022
by Vasiliy Kulakov
7.6k points
1 answer
2 votes
9.7k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!