Question

.

Determine the temperature of .084 moles of CO2 gas at 790 mmHg
which occupies a volume of 2.1L

Answer 1

Step-by-step explanation:

Molar volume at STP = 22.4L

So 0.084 mole of CO2 at STP has volume of 22.4*0.084 = 1.882L

Combined Gas Law: P1V1/T1 = P2V2/T2

760*1.882/273 = 790*2.1/Temperature

Temperature = 790*2.1*273/760/1.882

= 316.6K