Question

A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N and the coefficient of kinetic friction is 0.03. What is the net force applied to the motorcycle?

Answer 1

205N

Step-by-step explanation:

The net force (F) is the difference between the applied force(
`F_(A)`) and the kinetic frictional force(
`F_(R)`). i.e

F =
`F_(A)` -
`F_(R)` -----------------(i)

Note that;

`F_(R)` = μmg

Where;

μ = coefficient of kinetic friction

m = mass of the body

g = acceleration due to gravity = 10m/s²

Equation (i) then becomes;

F =
`F_(A)` - μmg -------------------(ii)

Given from question;

m = mass of motorcycle = 150kg

μ = 0.03

`F_(A)` = 250N

Substitute these values into equation (ii) as follows;

F = 250 - (0.03 x 150 x 10)

F = 250 - (45)

F = 205N

Therefore, the net force applied to the motorcycle is 205N