Question

3. At 10.0°C and 2.00 atm, the volume of the gas is 75.0 mL. If the temperature of the gas increases to

35.0°C and the pressure decreases to 1.00 atm, what is the new volume?
a. 1630 mL
b. 138 ml
c. 163 mL
d. 0.0017mL

Answer 1

Step-by-step explanation:

c.

`from \\ (P _(1) V _(1) )/(T _(1)) = (P _(2) V _(2))/(T _(2)) \\ (2 * 75)/((10+273)) = (V _(2) * 1)/((35+273)) \\V _(2) = (2 * 75 * (35+273))/((10+273) * 1) \\ V _(2) = 163 \: ml`