asked 56.1k views
2 votes
In ΔIJK, j = 770 cm, ∠I=88° and ∠J=15°. Find the area of ΔIJK, to the nearest 10th of a square centimeter.

asked
User Ulatekh
by
8.0k points

2 Answers

4 votes

1

(770)(2898.8011666)sin88

Plug in S.A.S. values.

Area

1115358.589

1115358.6

Area≈1115358.589≈1115358.6

Explanation:

answered
User Samarth Bhargava
by
8.9k points
4 votes

Answer: 1115358.6

Explanation:

answered
User Sneaky
by
7.6k points

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