Solid AgCl (Ksp = 1.8 X 10-10) is placed in a beaker of water. After a period of time, the Ag+ concentration is measured and found to be 2.5 X 10-7 M. a) What is the concentrati…

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Steven Fisher · Answer 1 · 2022-09-07T01:29:10+0000

Step-by-step explanation:

a)

$k _(sp) = [Ag {}^( + ) ][Cl {}^( - ) ] \\ but \: [Ag {}^( + ) ] = [Cl {}^( - ) ] \\ k _(sp) = [Ag {}^( + ) ] {}^(2) \\ [Ag {}^( + ) ] = \sqrt{k _(sp)} \\ = \sqrt{1.8 * {10}^( - 10) } \\ = 1.34 * {10}^( - 5) mol {dm}^( - 3)$

b)

It has not reached equilibrium because the silver concentration is not yet equal to the value of Ksp.

c)

Yes it will dissolve in order to establish the equilibrium.

Solid AgCl (Ksp = 1.8 X 10-10) is placed in a beaker of water. After a period of time, the Ag+ concentration is measured and found to be 2.5 X 10-7 M. a) What is the concentrati…

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