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Probability distribution

Probability distribution-example-1
asked
User TCC
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8.5k points

1 Answer

6 votes

Answer:

a) The value of q is 0.2.

b) E(X) = 1.85.

Explanation:

Question a:

The sum of all the probabilities must be 1. So


0.3 + x + 0.1 + 0.15 + 0.25 = 1


x + 0.8 = 1


x = 0.2

The value of q is 0.2.

Question b:

Multiplication of each value of x by its probability. So


E(X) = 0*0.3 + 1*0.2 + 2*0.1 + 3*0.15 + 4*0.25 = 1.85

So the answer is E(X) = 1.85.

answered
User Elbe
by
8.2k points

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