Question

Topic: Matrix Row Reduction

Answer 1

Write the system as an augmented matrix:

`\left[\begin{array}cc1&5&22\\4&-7&7\end{array}\right]`

Add -4 (row 1) to row 2 :

`\left[\begin{array}cc1&5&22\\0&-27&-81\end{array}\right]`

Multiply row 2 by -1/27 :

`\left[\begin{array}c1&5&22\\0&1&3\end{array}\right]`

Add -5 (row 2) to row 1 :

`\left[\begin{array}c1&0&7\\0&1&3\end{array}\right]`

Then x = 7 and y = 3.