Question

4. Calculate the final temperature of 75.4 g water originally at 12.6 °C after it absorbs 3.85 kcal

of heat.

Answer 1

63.7 °C

Step-by-step explanation:

Step 1: Given and required data

• Mass of water (m): 75.4 g

• Initial temperature (T₁): 12.6 °C

• Absorbed heat (Q): 3.85 kcal

• Specific heat capacity of water (c): 1 cal/g.°C

Step 2: Calculate the final temperature of the water (T₂)

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = Q/c × m + T₁

T₂ = 3.85 × 10³ cal/(1 cal/g.°C) × 75.4 g + 12.6 °C = 63.7 °C