Question

The Volume of a gas is measured to be 675.6 mL at 61.8 C. If the volume of the gas were changed to 410.9 mL, what would the final temperature be?

Answer 1

203.63 K

Step-by-step explanation:

Using Charles law equation,

V1/T1 = V2/T2

Where;

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information in this question,

V1 = 675.6 mL

V2 = 410.9 mL

T1 = 61.8°C = 61.8 + 273 = 334.8K

T2 = ?

Using V1/T1 = V2/T2

675.6/334.8 = 410.9/T2

Cross multiply

675.6 × T2 = 334.8 × 410.9

675.6T2 = 137569.32

T2 = 137569.32 ÷ 675.6

T2 = 203.63 K