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How much heat is gained by 1.25 grams of ice?

asked
User Tnull
by
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1 Answer

4 votes

Answer:

Heat gained by 1.25 grams of ice is 250 joules

Step-by-step explanation:

As we know


Q = mc\DeltaT

Where


\DeltaT is the change in temperature

Water freezes at 273.15 K/0 degree Celsius, and it boils at 373.15 K/00 degree Celsius,


\DeltaT

m is the mass in grams

c is the specific heat of water (ice) = 2.05 joules/gram

Substituting the given values, we get -


Q = 1.25 * 2.0 * 100\\Q = 250Joules.

answered
User Kjell Rilbe
by
8.0k points

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