Answer:
math = 24 
English = 16 
Philosophy = 8
Step-by-step explanation:
Given that the college needs to make 8 less English courses available compared to math In each quarter 
Let English = x , math = x + 8 ( in each quarter )
philosophy demand by student in each quarter = 1/2*x = x/2
limit of all three courses in a classroom = 48 
i.e. x + (x+ 8 ) + x/2 = 48 
 = 2x + x/2 = 48 - 8 
 = 2x + x/2 = 40 ∴ 5x / 2 = 40 
hence : x = 80 / 5 = 16
The number of sections of each course that the college should make available in each quarter to meet demand 
math = x + 8 = 16 + 8 = 24 
English = x = 16 
Philosophy = x/2 = 16 / 2 = 8