Question

In parallelogram ABCD, the coordinates of A are (3,-1) and the coordinates of C are (-1,5). What are the coordinates of the point of intersection of the diagonals?

Answer 1

The coordinates of the point of intersection of the diagonals in parallelogram ABCD are (1, 2).

Step-by-step explanation:

To find the coordinates of the point of intersection of the diagonals in parallelogram ABCD, we need to find the midpoint of the line segment connecting points A and C. The x-coordinate of the midpoint is found by averaging the x-coordinates of points A and C, and the y-coordinate of the midpoint is found by averaging the y-coordinates of points A and C.

Given that point A has coordinates (3, -1) and point C has coordinates (-1, 5), the midpoint has coordinates:

x = (3 + (-1))/2 = 2/2 = 1

y = (-1 + 5)/2 = 4/2 = 2

So, the coordinates of the point of intersection of the diagonals are (1, 2).

Answer 2

I’m not sure bro ask one of your friends if they know if they don’t just ask your parents