Question

Help please Im giving brianless and 100 points to the person who answer and show their work thank you very much

Answer 1

• Base=35-9-12.5=12.5ft=B
• Perpendicular=p
• \theta= 16.5°

Now

`\\ \rm\Rrightarrow tan\theta=(P)/(B)`

`\\ \rm\Rrightarrow tan16.5=(P)/(13.5)`

`\\ \rm\Rrightarrow P=13.5tan16.5`

`\\ \rm\Rrightarrow P=13.5(0.3)`

`\\ \rm\Rrightarrow P\approx 4ft`

Answer 2

8.5 ft (nearest tenth)

Explanation:

To find the depth of the pool at the deep end, we need to find the height of the right triangle with angle 16.5° and add it to 4.5 ft

Base of the triangle = 35 - 9 - 12.5 = 13.5 ft

Use the tan trig ratio:

`\tan(x)=(O)/(A)`

where x is the angle, O is the side opposite and angle and A is the side adjacent to the angle in a right triangle.

Given:

• x = 16.5°
• O = h (height)
• A = 13.5 ft

`\implies\tan(16.5)=(h)/(13.5)\\\\\implies h= 13.5\tan(16.5)\\\\\implies h = 4.0 \textsf{ ft (nearest tenth)}`

Therefore, the depth of the pool at the deepest end = 4 + 4.5 = 8.5 ft (nearest tenth)