Question

Determine the equilibrium constant for the system N204 = 2NO2 at 25°C.

The concentrations are shown here: [N2O4]= 2.48x10-2M, [NO_]=1.41x10-2M.
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Answer 1

Answer: K = 8.01 ·10^-3 M

Explanation: K = [NO2] ² / [N2O4] = (0.0141 M)² / 0.0248 M = 0.00801 M