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How to write an equation in standard form for a circle of other radius 3 centered at the origin

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User Prekolna
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2 Answers

2 votes

Answer:


from \: general \: equation \\ {x}^(2) + {y}^(2) + 2gx + 2fy + c = 0 \\ at \: the \: origin \: \: g = 0 \: and \: f = 0 \\since \: c = {g}^(2) + {f}^(2) + {r}^(2) \\ whe re \: r \: is \: radius \\ therefore \: c = {3}^(2) = 9 \\ = > {x}^(2) + {y}^(2) + 9 = 0

answered
User Francisco QV
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8.9k points
5 votes

Answer:

What is the diameter of a circle if the radius is 3

answered
User Kettly
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8.2k points

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