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Whats y=-4(x+1)^2-5 in standard form

Whats y=-4(x+1)^2-5 in standard form
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Whats y=-4(x+1)^2-5 in standard form

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User Bruno Lavit
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2 Answers

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Answer:

4x^2 − 8x + 9

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User BJ Miller
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2 votes

Answer:

y = - 4 (x+ 1)^2 - 5 in standard form is

y = -4x^2 - 8x - 9

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User Tasheena
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