asked 109k views
2 votes
Please help its due tonight!!! also no links allowed.

When 28,242 J are transferred to a water sample, it's temperature increases from 18⁰C to 63⁰C. Determine the mass of the water sample.

asked
User Alfreema
by
8.0k points

2 Answers

6 votes
Just do £.15 breakfast
answered
User Mohamed Elgazar
by
8.4k points
5 votes

Answer:

149.79 grams.

Step-by-step explanation:

Formula

Joules = m * c * delta (t)

Givens

J = 28242

m = ?

c = 4.19

Δt = 63 - 18 = 45

Solution

28242 = m * 4.19 * 45

28242 = m * 188.55

m = 28242 / 188.55

m = 149.79

answered
User Wuxb
by
8.6k points
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