Question

Given the function w(t) = 15t - 1, w(-1/3)=?​

Answer 1

-6

Explanation:

substitute -1/3 into w(t) = 15t - 1

=> w(-1/3) = 15(-1/3) - 1

=> w(-1/3) = -6

Answer 2

-6

Explanation:

Plug in -1/3for t

W(-1/3)=15(-1/3)-1=-5-1=-6