Question

Find the 96th term of the arithmetic sequence 1, -12, -25, ...

Answer 1

The 96th term of the arithmetic sequence is -1234.

Explanation:

first term (a)=1

second term (t2)=-12

common difference (d)= t2-a

d=-12-1

d=-13

96th term (t96)=?

We know that,

t96=a+(n-1)d

t96=1+(96-1)(-13)

t96=1+95(-13)

t96=1-1235

t96=-1234