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(1/6)^p = 36^3 x 6^18. What is the value of p?

(1/6)^p = 36^3 x 6^18. What is the value of p?
asked 28.6k views
3 votes
(1/6)^p = 36^3 x 6^18. What is the value of p?

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User Eben Geer
by
8.5k points

1 Answer

3 votes

Answer:

Explanation:

(1/6)^p=36^3×6^18


((1)/(6)) ^p=(6^2)^3 * 6^(18)\\(1)/(6^p) =6^(2 * 3) * 6^ {18}\\6^(-p)=6^6 * 6^(18)\\=6^(6+18)\\=6^(24)\\-p=24\\p=-24

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User Piotrp
by
8.1k points
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