asked 106k views
1 vote
The radius of the base of a cone is 4 inches. The slant height of the cone is

6 inches. Which is closest to the surface area of the cone?
F 75 sq in.
100 sq in.
H 126 sq in.
J 188 sq in.

asked
User VInayK
by
7.8k points

1 Answer

7 votes

Question:-

The radius of the base of a cone is 4 inches. The slant height of the cone is 6 inches. Which is closest to the surface area of the cone ?

Answer:-

Given:-


\bullet Radius (r) of the base of a cone is 4 inches.


\bullet Slant height (l) of the cone is 6 inches.

To Find:-

Which is closest to the surface area of the cone ?

Solution:-

We know,

Formula of surface area of a cone is πr(r + l) sq. units.

Taking value of π = 3.14

So, Surface area of the cone = 3.14 × 4(4 + 6)

Surface area of the cone = 12.56 × 10

Surface area of the cone = 125.6 sq. inches.


\because 126 sq. inches is closest to 125.6 sq. inches.

So, option (H) 126 sq. in is correct. [Answer]

answered
User Jsheeran
by
8.4k points
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